PipeChat Digest #794 - Tuesday, April 13, 1999
 
Re: 128' Novelties...
  by "Matt Baker" <poinsettia@netxn.com>
Re: ULF Waves
  by "Matt Baker" <poinsettia@netxn.com>
 


(back) Subject: Re: 128' Novelties... From: Matt Baker <poinsettia@netxn.com> Date: Tue, 13 Apr 1999 01:05:22 -0700   Kevin Cartwright wrote:   > There is > also a formula for finding any pitch at A=440 Hz (a-0). I can't > remember it now, but will get my "little black book" and find it; will > post tomorrow.   Multiply the frequency of a note with the 12th-root of 2 (1.059463094) to get the note immediately above it, or divide to get the note below it.   Doing this with 440 you get:   440 (A) x 1.059463094 = 466.1637615 (B-flat) x 1.059463094 = 493.8833013 (B) x 1.059463094 = 523.2511306 (C) x 1.059463094 = 554.365262 (D-flat) x 1.059463094 = 587.3295358 (D) x 1.059463094 = 622.2539674 (E-flat) x 1.059463094 = 659.2551138 (E) x 1.059463094 = 698.4564629 (F) x 1.059463094 = 739.9888454 (G-flat) x 1.059463094 = 783.990872 (G) x 1.059463094 = 830.6093952 (A-flat) x 1.059463094 = 880 (A)   Or keep dividing by 1.059463094 to count down. And of course you can multiply or divide a note by powers of 2 to get octaves.   Or to simplify, just raise the 12th-root of 2 to the power of the number of notes you want to count up or down and multiply or divide your starting frequency by it. To figure out F above A you would: 440 x (1.059463094 ^ 8) = 698.4564629 ( X ^ Y means X to the power of Y, in other words X times itself Y times), and F is 8 notes above A)   You can also do this on any equal-tempered scale using any number of notes per octave. It's just X-th root of 2, where X is the number of notes per octave. For example, to get the frequencies on a 30-band 1/3-ocrtave equalizer you use the cube(3rd)-root of 2 (1.25992105) and start with a standard frequency such as 1000Hz.   -- < Transmit src: poinsettia@netxn.com ID1 LCARS Channel 1 Lineout > <YuSeEkMeAtNo31101993 http://www.netxn.com/~poinsettia/index.html>      
(back) Subject: Re: ULF Waves From: Matt Baker <poinsettia@netxn.com> Date: Tue, 13 Apr 1999 01:28:16 -0700   To cause any significant pain you'd probably need amplitude a lot higher than anything you'd find in an average organ. 128' Double-sub-contra Ophicleide Magna en-chamade on 500" of wind maybe? :-) It'd be really "loud", just not audible. Do this at 1000Hz and the local glazier [sp?] would get a lot of business!   Kevin Cartwright wrote:   > > pedalboard. This reminds me of an experiment somebody told me about where a > > really big trumpet-of-sorts that sounded at 4Hz and 2Hz was demonstrated at a > > convention--supposedly it caused pain for everybody when sounded! > > Yes, the U.S. Government knows this as well; they like to test ultra low > frequency waves for defense purposes, as well as long range > communication underwater. Anyone care to elaborate?? All I've really > heard is rumors. BUT, is it thought that prolonged exposure to even 32' > and 64' stops can be painful for an "organ crawler." If I build a 128' > stop, it will be just a reed, with a short resonator, so the sound can't > really form a "harmful resonation/tone." I think they based a > science-fiction show episode on this concept once... I think it was > "X-Files" or something? > > Anywho, back to organs...the new weapon of choice. ;-) Tee-hee-hee...   -- < Transmit src: poinsettia@netxn.com ID1 LCARS Channel 1 Lineout > <YuSeEkMeAtNo31101993 http://www.netxn.com/~poinsettia/index.html>